Given,

So, let where a,b,c,d {0,1,2}

So, total sample space will be 3 4 = 81

Now we will find or possibilities for |M| =0

So, for |M| = 0 cases will be,

1. or or Total matrix = 3

2. Two 1's and Two 0's Total matrix = 4

3. Two 2's and Two 0's Total matrix = 4

4. Two 1's and Two 2's Total matrix= 4

5. One 1’s and three 0's Total matrix = 4

6. One 2 and Three 0's Total matrix = 4

7. One 1 and one 2 and two 0's Total matrix = 8

So, total cases for which |M|= 0 is 31,

So probability will be

Hence,

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